Show/hide website content based upon URL parameters in php
Steps to use the code
- You must have a domain
- Copy and paste the below code into the index.php file
What is the purpose of this code?
This code is used to hide/show the website content based upon the passed parameter in the given URL. For example: If you want to show a blank page on your website when visitors visit your domain.com but want to show the content only if a specific parameter is passed inside a website domain. (domain.com/keyfound)
In other words, Blank page on domain.com and show website content on domain.com/keyfound.
Method 1
$url = (isset($_SERVER['HTTPS']) && $_SERVER['HTTPS'] ==='on' ? "https":"http") . "://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]";
$data = parse_url($url);
//print_r($data);
if(!empty($data['query'])){
if($data['query'] == '123')
echo "show website content!";
}else{
exit();
}Method 2
if(isset($_GET['key']) && !empty( $_GET['key'])){
if($_GET['key'] == '123')
echo "website content";
}else{
exit();
}
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